By allowing you to respond selectively to different situations and conditions, if statements open up whole new possibilities for your programs. In this section, you will learn how to test for certain conditions, and then respond in appropriate ways to those conditions.
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# A list of desserts I like.
desserts = ['ice cream', 'chocolate', 'apple crisp', 'cookies']
favorite_dessert = 'apple crisp'
# Print the desserts out, but let everyone know my favorite dessert.
for dessert in desserts:
if dessert == favorite_dessert:
# This dessert is my favorite, let's let everyone know!
print("%s is my favorite dessert!" % dessert.title())
else:
# I like these desserts, but they are not my favorite.
print("I like %s." % dessert)
You can test as many conditions as you want in an if statement, as you will see in a little bit.
Every if statement evaluates to True or False. True and False are Python keywords, which have special meanings attached to them. You can test for the following conditions in your if statements:
Remember learning about PEP 8? There is a section of PEP 8 that tells us it's a good idea to put a single space on either side of all of these comparison operators. If you're not sure what this means, just follow the style of the examples you see below.
Two items are equal if they have the same value. You can test for equality between numbers, strings, and a number of other objects which you will learn about later. Some of these results may be surprising, so take a careful look at the examples below.
In Python, as in many programming languages, two equals signs tests for equality.
Watch out! Be careful of accidentally using one equals sign, which can really throw things off because that one equals sign actually sets your item to the value you are testing for!
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5 == 5
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3 == 5
Out[4]:
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5 == 5.0
Out[24]:
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'eric' == 'eric'
Out[8]:
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'Eric' == 'eric'
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'Eric'.lower() == 'eric'.lower()
Out[10]:
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'5' == 5
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'5' == str(5)
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Two items are inequal if they do not have the same value. In Python, we test for inequality using the exclamation point and one equals sign.
Sometimes you want to test for equality and if that fails, assume inequality. Sometimes it makes more sense to test for inequality directly.
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3 != 5
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5 != 5
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'Eric' != 'eric'
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5 > 3
Out[16]:
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5 >= 3
Out[19]:
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3 >= 3
Out[20]:
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3 < 5
Out[21]:
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3 <= 5
Out[22]:
In [23]:
3 <= 3
Out[23]:
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vowels = ['a', 'e', 'i', 'o', 'u']
'a' in vowels
Out[25]:
In [26]:
vowels = ['a', 'e', 'i', 'o', 'u']
'b' in vowels
Out[26]:
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# Ex 5.1 : True and False
# put your code here
In [27]:
dogs = ['willie', 'hootz', 'peso', 'juno']
if len(dogs) > 3:
print("Wow, we have a lot of dogs here!")
In this situation, nothing happens if the test does not pass.
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dogs = ['willie', 'hootz']
if len(dogs) > 3:
print("Wow, we have a lot of dogs here!")
Notice that there are no errors. The condition len(dogs) > 3
evaluates to False, and the program moves on to any lines after the if block.
In [30]:
dogs = ['willie', 'hootz', 'peso', 'juno']
if len(dogs) > 3:
print("Wow, we have a lot of dogs here!")
else:
print("Okay, this is a reasonable number of dogs.")
Our results have not changed in this case, because if the test evaluates to True only the statements under the if statement are executed. The statements under else area only executed if the test fails:
In [31]:
dogs = ['willie', 'hootz']
if len(dogs) > 3:
print("Wow, we have a lot of dogs here!")
else:
print("Okay, this is a reasonable number of dogs.")
The test evaluated to False, so only the statement under else
is run.
Many times, you will want to test a series of conditions, rather than just an either-or situation. You can do this with a series of if-elif-else statements
There is no limit to how many conditions you can test. You always need one if statement to start the chain, and you can never have more than one else statement. But you can have as many elif statements as you want.
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dogs = ['willie', 'hootz', 'peso', 'monty', 'juno', 'turkey']
if len(dogs) >= 5:
print("Holy mackerel, we might as well start a dog hostel!")
elif len(dogs) >= 3:
print("Wow, we have a lot of dogs here!")
else:
print("Okay, this is a reasonable number of dogs.")
It is important to note that in situations like this, only the first test is evaluated. In an if-elif-else chain, once a test passes the rest of the conditions are ignored.
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dogs = ['willie', 'hootz', 'peso', 'monty']
if len(dogs) >= 5:
print("Holy mackerel, we might as well start a dog hostel!")
elif len(dogs) >= 3:
print("Wow, we have a lot of dogs here!")
else:
print("Okay, this is a reasonable number of dogs.")
The first test failed, so Python evaluated the second test. That test passed, so the statement corresponding to len(dogs) >= 3
is executed.
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dogs = ['willie', 'hootz']
if len(dogs) >= 5:
print("Holy mackerel, we might as well start a dog hostel!")
elif len(dogs) >= 3:
print("Wow, we have a lot of dogs here!")
else:
print("Okay, this is a reasonable number of dogs.")
In this situation, the first two tests fail, so the statement in the else clause is executed. Note that this statement would be executed even if there are no dogs at all:
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dogs = []
if len(dogs) >= 5:
print("Holy mackerel, we might as well start a dog hostel!")
elif len(dogs) >= 3:
print("Wow, we have a lot of dogs here!")
else:
print("Okay, this is a reasonable number of dogs.")
Note that you don't have to take any action at all when you start a series of if statements. You could simply do nothing in the situation that there are no dogs by replacing the else
clause with another elif
clause:
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###highlight=[8]
dogs = []
if len(dogs) >= 5:
print("Holy mackerel, we might as well start a dog hostel!")
elif len(dogs) >= 3:
print("Wow, we have a lot of dogs here!")
elif len(dogs) >= 1:
print("Okay, this is a reasonable number of dogs.")
In this case, we only print a message if there is at least one dog present. Of course, you could add a new else
clause to respond to the situation in which there are no dogs at all:
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###highlight=[10,11]
dogs = []
if len(dogs) >= 5:
print("Holy mackerel, we might as well start a dog hostel!")
elif len(dogs) >= 3:
print("Wow, we have a lot of dogs here!")
elif len(dogs) >= 1:
print("Okay, this is a reasonable number of dogs.")
else:
print("I wish we had a dog here.")
As you can see, the if-elif-else chain lets you respond in very specific ways to any given situation.
crowd_test
.else
statement to your if tests. If the else
statement is run, have it print a message that the room is not very crowded.
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# Ex 5.2 : Three is a Crowd
# put your code here
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# Ex 5.3 : Three is a Crowd - Part 2
# put your code here
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# Ex 5.4 : Six is a Mob
# put your code here
In all of the examples we have seen so far, only one test can pass. As soon as the first test passes, the rest of the tests are ignored. This is really good, because it allows our code to run more efficiently. Many times only one condition can be true, so testing every condition after one passes would be meaningless.
There are situations in which you want to run a series of tests, where every single test runs. These are situations where any or all of the tests could pass, and you want to respond to each passing test. Consider the following example, where we want to greet each dog that is present:
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dogs = ['willie', 'hootz']
if 'willie' in dogs:
print("Hello, Willie!")
if 'hootz' in dogs:
print("Hello, Hootz!")
if 'peso' in dogs:
print("Hello, Peso!")
if 'monty' in dogs:
print("Hello, Monty!")
If we had done this using an if-elif-else chain, only the first dog that is present would be greeted:
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###highlight=[6,7,8,9,10,11]
dogs = ['willie', 'hootz']
if 'willie' in dogs:
print("Hello, Willie!")
elif 'hootz' in dogs:
print("Hello, Hootz!")
elif 'peso' in dogs:
print("Hello, Peso!")
elif 'monty' in dogs:
print("Hello, Monty!")
Of course, this could be written much more cleanly using lists and for loops. See if you can follow this code.
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dogs_we_know = ['willie', 'hootz', 'peso', 'monty', 'juno', 'turkey']
dogs_present = ['willie', 'hootz']
# Go through all the dogs that are present, and greet the dogs we know.
for dog in dogs_present:
if dog in dogs_we_know:
print("Hello, %s!" % dog.title())
This is the kind of code you should be aiming to write. It is fine to come up with code that is less efficient at first. When you notice yourself writing the same kind of code repeatedly in one program, look to see if you can use a loop or a function to make your code more efficient.
Take a look at the following examples, keep them in mind, and test any value you are curious about.
I am using a slightly longer test just to make sure something gets printed each time.
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if 0:
print("This evaluates to True.")
else:
print("This evaluates to False.")
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if 1:
print("This evaluates to True.")
else:
print("This evaluates to False.")
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# Arbitrary non-zero numbers evaluate to True.
if 1253756:
print("This evaluates to True.")
else:
print("This evaluates to False.")
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# Negative numbers are not zero, so they evaluate to True.
if -1:
print("This evaluates to True.")
else:
print("This evaluates to False.")
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# An empty string evaluates to False.
if '':
print("This evaluates to True.")
else:
print("This evaluates to False.")
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# Any other string, including a space, evaluates to True.
if ' ':
print("This evaluates to True.")
else:
print("This evaluates to False.")
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# Any other string, including a space, evaluates to True.
if 'hello':
print("This evaluates to True.")
else:
print("This evaluates to False.")
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# None is a special object in Python. It evaluates to False.
if None:
print("This evaluates to True.")
else:
print("This evaluates to False.")
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# Overall Challenge: Alien Points
# Put your code here
These are placed at the bottom, so you can have a chance to solve exercises without seeing any hints.
current_score
or current_points
equal to 0.current_score = current_score + points
, where points is the number of points for the current alien.